- 问答
最小花费那道题还是有问题
- @ 2026-10-29 17:44:22
#include <bits/stdc++.h>
using namespace std;
typedef pair<double, int> PII;
const int N = 2010;
int n, m;
int h[N], e[N], ne[N], idx;
double w[N];
double dist[N];
bool st[N];
int A,B;
void add(int a, int b, double c)
{
e[idx] = b, w[idx] = c, ne[idx] = h[a], h[a] = idx ++ ;
}
double dijkstra(int x,int y)
{
for(int i=0;i<N;i++){
dist[i]=nextafter(1.0, 0.0);
}
dist[x] = 1.0;
priority_queue<PII, vector<PII>, greater<PII>> heap;
heap.push({1.0, x});
while (heap.size())
{
auto t = heap.top();
heap.pop();
int ver = t.second, distance = t.first;
if (st[ver]) continue;
st[ver] = true;
for (int i = h[ver]; i != -1; i = ne[i])
{
int j = e[i];
if (dist[j] < dist[ver] * w[i])
{
dist[j] = dist[ver] * w[i];
heap.push({dist[j], j});
}
}
}
return dist[y];
}
int main(){
cin >> n >> m;
memset(h, -1, sizeof h);
while (m -- )
{
int a, b, c;
cin >> a >> b >> c;
int wc=1-double(c)/100;
add(a, b, wc);
add(b, a, wc);
}
cin >> A >> B;
double ll=dijkstra(A,B);
long double result=100/ll;
printf("%.8lf",result);
return 0;
}
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